Ben-Tal et al. (1994) Problem 1 in Floudas et al. [7]

Jsun Yui Wong

The computer program listed below seeks to solve the following problem of seven continuous variables from Floudas et al. [7, pp. 38-39]:

Maximize (9 – 6 * X(1) – 16 * X(2) – 15 * X(3)) * X(4) + (15 – 6 * X(1) – 16 * X(2) – 15 * X(3)) * X(5) – X(6) + 5 * X(7)

subject to

X(3) * X(4) + X(3) * X(5)<=50

X(4) +- X(6)<=100

X(5) + X(7)<=200

(3 * X(1) + X(2) + X(3) – 2.5) * X(4) – .5 * X(6)<=0

(3 * X(1) + X(2) + X(3) – 1.5) * X(5) + .5 * X(7)<=0

X(1) + X(2) + X(3)=1

0<= X(1) <= 1

0<= X(2) <= 1

0<= X(3) <= 1

0<= X(4) <= 100

0<= X(5) <= 200

0<= X(6) <= 100

0<= X(7) <= 200.

In the following computer program, D of line 81 stands for discreteness, and X(8) through X(12) are slack variables.

 

0 DEFDBL A-Z

2 DEFINT K

3 DIM B(99), N(99), A(99), H(99), L(99), U(99), X(1111), D(111), P(111), PS(33)

12 FOR JJJJ = -32000 TO 32000 STEP .01

 

14 RANDOMIZE JJJJ

16 M = -1D+37

81 D(1) = .0001

 

85 D(2) = .0001

86 D(3) = .0001

87 D(4) = .001

88 D(5) = .001

89 D(6) = .001

90 D(7) = .001

 

91 A(1) = FIX(RND * 1.01)
93 A(2) = FIX(RND * 1.01)
94 A(3) = FIX(RND * 1.01)

95 A(4) = FIX(RND * 101)
96 A(5) = FIX(RND * 201)

 

98 A(6) = FIX(RND * 101)
99 A(7) = FIX(RND * 201)

 

128 FOR I = 1 TO 10000

 

129 FOR KKQQ = 1 TO 7

130 X(KKQQ) = A(KKQQ)
131 NEXT KKQQ
133 FOR IPP = 1 TO (1 + FIX(RND * 3))

181 j = 1 + FIX(RND * 7)

189 REM r = (1 – RND * 2) * A(j)
190 REM X(j) = A(j) + (RND ^ (RND * 10)) * r
195 IF RND < .5 THEN X(j) = A(j) – INT(RND * 10) * D(j) ELSE X(j) = A(j) + INT(RND * 10) * D(j)

222 NEXT IPP
223 REM FOR J44 = 4 TO 7
224 REM X(J44) = INT(X(J44))

225 REM NEXT J44

 

226 FOR J44 = 1 TO 7
227 IF X(J44) < 0## THEN 1670

229 NEXT J44
235 IF X(1) > 1## THEN 1670

 

236 IF X(2) > 1## THEN 1670

 

237 IF X(3) > 1## THEN 1670

 

238 IF X(4) > 100## THEN 1670

 

239 IF X(5) > 200## THEN 1670
240 IF X(6) > 100## THEN 1670

 

241 IF X(7) > 200## THEN 1670

 

246 X(1) = 1 – X(2) – X(3)

247 X(8) = 100 – X(4) – X(6)

249 X(9) = 200 – X(5) – X(7)
251 X(10) = 50 – X(3) * X(4) – X(3) * X(5)

 

277 X(11) = -(3 * X(1) + X(2) + X(3) – 2.5) * X(4) + .5 * X(6)
279 X(12) = -(3 * X(1) + X(2) + X(3) – 1.5) * X(5) – .5 * X(7)

 

326 FOR J44 = 1 TO 7
327 IF X(J44) < 0## THEN 1670

329 NEXT J44
335 IF X(1) > 1## THEN 1670

 

336 IF X(2) > 1## THEN 1670

 

337 IF X(3) > 1## THEN 1670

 

338 IF X(4) > 100## THEN 1670

 

339 IF X(5) > 200## THEN 1670
340 IF X(6) > 100## THEN 1670

 

341 IF X(7) > 200## THEN 1670

 

450 FOR J47 = 8 TO 12

 

451 IF X(J47) < 0 THEN X(J47) = X(J47) ELSE X(J47) = 0

452 NEXT J47

 

453 POBA = (9 – 6 * X(1) – 16 * X(2) – 15 * X(3)) * X(4) + (15 – 6 * X(1) – 16 * X(2) – 15 * X(3)) * X(5) – X(6) + 5 * X(7) + 1000000 * (X(8) + X(9) + X(10) + X(11) + X(12))

466 P = POBA

1111 IF P <= M THEN 1670

 

1450 M = P
1454 FOR KLX = 1 TO 12

1455 A(KLX) = X(KLX)
1456 NEXT KLX
1557 GOTO 128

1670 NEXT I
1889 IF M < 449.95 THEN 1999

1907 PRINT A(1), A(2), A(3), A(4), A(5), A(6), A(7), A(8)
1908 PRINT A(9), A(10), A(11), A(12), M, JJJJ

1999 NEXT JJJJ

This BASIC computer program was run with QB64v1000-win [54]. The complete output through JJJJ = -31999.97000000001 is shown below:

1.27675647831893D-15          .4999999999999991          .4999999999999996
1.413799632921098D-15          99.99999999999945          9.999999970941873D-04
100.00000000001          0
-9.407585821463727D-12          0          0          -5.506706202140776D-12
449.9989850857623          -32000

2.109423746787797D-15          .4999999999999997          .5000000000000001
9.99999998975422D-04          99.998999999999983          9.9999999968006617D-04
99.999000000000885          0
0          0          0          -4.931166586175095D-12
449.98799506889          -31999.97000000001

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen. On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and QB64v1000-win [54], the wall-clock time (not CPU time) for obtaining the output through JJJJ = -31999.97000000001 was 4 seconds, not including the time for “Creating .EXE file” (12 seconds, total, including the time for “Creating .EXE file.”) One can compare the computational results above with those on pp. 39-40 of Floudas et al. [7, pp. 39-40].

Acknowledgment

I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

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