Solving a Nonlinear Programming Problem Involving a Product of  3 Nonlinear Functions

 

Jsun Yui Wong

The computer program listed below seeks to solve the following problem in Shen, Zhang, and Wang [31, p. 12 of 16, Example 4]:

Minimize ((X(1) – 1) ^ 2 + (X(2) – 1) ^ 2 + 1) * ((X(1) – 2) ^ 2 + (X(2) – 3) ^ 2 + 1) * ((X(1) – 4) ^ 2 + (X(2) – 2) ^ 2 + 1)

subject to

X(1) + 2*X(2)<=10,

0<=X(1) <= 10,

.0<=X(2) <= 4.

X(3) below is an added slack variable.

0 DEFDBL A-Z

2 DEFINT K

3 DIM B(99), N(99), A(99), H(99), L(99), U(99), X(1111), D(111), P(111), PS(33)

12 FOR JJJJ = -32000 TO 32000 STEP .01

14 RANDOMIZE JJJJ
16 M = -1D+37

72 A(1) = RND * 10

75 A(2) = RND * 4

128 FOR I = 1 TO 2000

 

129 FOR KKQQ = 1 TO 2

130 X(KKQQ) = A(KKQQ)
131 NEXT KKQQ
133 FOR IPP = 1 TO (1 + FIX(RND * 2))

 

181 J = 1 + FIX(RND * 2)

183 r = (1 – RND * 2) * A(J)
187 X(J) = A(J) + (RND ^ (RND * 10)) * r

191 NEXT IPP

 

201 IF X(1) < 0 THEN 1670
203 IF X(1) > 10 THEN 1670

211 IF X(2) < 0 THEN 1670
213 IF X(2) > 4 THEN 1670

311 X(3) = 10 – X(1) – 2 * X(2)

 

333 FOR J44 = 3 TO 3

 

336 IF X(J44) < 0 THEN X(J44) = X(J44) ELSE X(J44) = 0

339 NEXT J44
388 POBA = -((X(1) – 1) ^ 2 + (X(2) – 1) ^ 2 + 1) * ((X(1) – 2) ^ 2 + (X(2) – 3) ^ 2 + 1) * ((X(1) – 4) ^ 2 + (X(2) – 2) ^ 2 + 1) + 1000000 * (X(3))

 

466 P = POBA

1111 IF P <= M THEN 1670

 

1452 M = P
1454 FOR KLX = 1 TO 3

1459 A(KLX) = X(KLX)
1460 NEXT KLX
1557 GOTO 128

1670 NEXT I

1889 IF M < -111111 THEN 1999

 

1900 PRINT A(1), A(2), A(3), M, JJJJ

1999 NEXT JJJJ

This BASIC computer program was run with qb64v1000-win [39]. The complete output through JJJJ = -31999.98 is shown below:

2.188967691603656          2.433096908147784          0
-27.08443533712395          -32000

2.188967706327333          2.433096919790813          0
-27.08443533712396          -31999.99

2.188967700758801          2.433096913634957          0
-27.08443533712395          -31999.98

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen. On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and qb64v1000-win [39], the wall-clock time for obtaining the output through
JJJJ= -31999.98 was 1 or 2 seconds, not including the time for “Creating .EXE file.” One can compare the computational results above to the results in Shen, Zhang, and Wang [31, p. 10 of 16, Table 1, Example 4].

Acknowledgment

I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

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