Solving a Nonlinear Fractional Programming Problem Involving 1 Nonlinear Numerator, 2 Nonlinear Denominators and 3 Nonlinear Constraints

 

Jsun Yui Wong

The computer program listed below seeks to solve the following problem from Shen, Ma, and Chen [30, p. 453, Example 6].

Maximize -(-1.35) * ((X(1) ^ 2 * X(2) ^ .5 – 2 * X(1) * X(2) ^ -1 + X(2) ^ 2 – 2.8 * X(1) ^ -1 * X(2) + 7.5) / (X(1) * X(2) ^ 1.5 + 1)) – (12.99) * ((X(2) + .1) / (X(1) ^ 2 * X(2) ^ -1 – 3 * X(1) ^ -1 + 2 * X(1) * X(2) ^ 2 – 9 * X(2) ^ -1 + 12))

subject to

2 * X(1) ^ -1 + X(1) * X(2)<=4,

X(1) +3 * X(1) ^ -1 * X(2)<=5,

X(1) ^ 2 – 3 * X(2) ^ 3<=2,

1<=X(1) <= 3,

1<=X(2) <= 3.

X(3) through X(5) below are added slack variables.

0 DEFDBL A-Z

2 DEFINT K

3 DIM B(99), N(99), A(99), H(99), L(99), U(99), X(1111), D(111), P(111), PS(33)

12 FOR JJJJ = -32000 TO 32000 STEP .01

14 RANDOMIZE JJJJ
16 M = -1D+37

72 A(1) = 1 + RND * 2

75 A(2) = 1 + RND * 2

128 FOR I = 1 TO 2000

 

129 FOR KKQQ = 1 TO 2

130 X(KKQQ) = A(KKQQ)
131 NEXT KKQQ
133 FOR IPP = 1 TO (1 + FIX(RND * 2))

 

181 J = 1 + FIX(RND * 2)

183 r = (1 – RND * 2) * A(J)
187 X(J) = A(J) + (RND ^ (RND * 10)) * r

191 NEXT IPP

 

201 IF X(1) < 1 THEN 1670
203 IF X(1) > 3 THEN 1670

211 IF X(2) < 1 THEN 1670
213 IF X(2) > 3 THEN 1670

311 X(3) = 4 – 2 * X(1) ^ -1 – X(1) * X(2)

313 X(4) = 5 – X(1) – 3 * X(1) ^ -1 * X(2)

 

315 X(5) = 2 – X(1) ^ 2 + 3 * X(2) ^ 3

 

333 FOR J44 = 3 TO 5
336 IF X(J44) < 0 THEN X(J44) = X(J44) ELSE X(J44) = 0

 

339 NEXT J44

378 POBA = -(-1.35) * ((X(1) ^ 2 * X(2) ^ .5 – 2 * X(1) * X(2) ^ -1 + X(2) ^ 2 – 2.8 * X(1) ^ -1 * X(2) + 7.5) / (X(1) * X(2) ^ 1.5 + 1)) – (12.99) * ((X(2) + .1) / (X(1) ^ 2 * X(2) ^ -1 – 3 * X(1) ^ -1 + 2 * X(1) * X(2) ^ 2 – 9 * X(2) ^ -1 + 12)) + 1000000 * (X(3) + X(4) + X(5))

 

466 P = POBA

1111 IF P <= M THEN 1670

 

1452 M = P
1454 FOR KLX = 1 TO 5

1459 A(KLX) = X(KLX)
1460 NEXT KLX
1557 GOTO 128

1670 NEXT I

1889 IF M < -11111 THEN 1999

1900 PRINT A(1), A(2), A(3), A(4), A(5), M, JJJJ

1999 NEXT JJJJ

This BASIC computer program was run with qb64v1000-win [38]. The complete output through JJJJ = -31999.98 is shown below:

2.698672512963932          1.207578072004017          0
0          0          2.332207556891017          -32000

2.698682666462486          1.20758224763645          0
0          0          2.332213594166706          -31999.99

2.698690059295716          1.20758528793531          0
0          0          2.332217989915511          -31999.98

Above there is no rounding by hand; it is just straight copying by hand from the monitor screen. On a personal computer with a Pentium Dual-Core CPU E5200 @2.50GHz, 2.50 GHz, 960 MB of RAM and qb64v1000-win [38], the wall-clock time for obtaining the output through
JJJJ= -31999.98 was 1 or 2 seconds, not including the time for “Creating .EXE file.” One can compare the computational results above to the results in Shen, Ma, and Chen [30, p.452, Table 1].

Acknowledgment

I would like to acknowledge the encouragement of Roberta Clark and Tom Clark.

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